Answer
$-3$
Work Step by Step
$
\begin{align}\det A &=
4\begin{vmatrix}0&3\\-2&5\end{vmatrix}-1\begin{vmatrix}4&3\\3&5\end{vmatrix}+2\begin{vmatrix}4&0\\3&-2\end{vmatrix}\\
&=4(0+6)-1(20-9)+2(-8-0)\\
&=24-11-16=-3
\end{align}
$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 3 - Determinants - 3.1 Exercises - Page 170: 8
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