Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 3 - Determinants - 3.1 Exercises - Page 170: 18

Answer

$-12$

Work Step by Step

$\det A=(1\cdot3\cdot2)+(3\cdot1\cdot3)+(4\cdot2\cdot3)-(3\cdot3\cdot4)-(3\cdot1\cdot1)-(2\cdot2\cdot3)=6+9+24-36-3-12=-12$
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