Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 3 - Determinants - 3.1 Exercises - Page 170: 16

Answer

$19$

Work Step by Step

$\det A=(0\cdot(-5)\cdot1)+(3\cdot0\cdot3)+(1\cdot4\cdot4)-(3\cdot(-5)\cdot1)-(4\cdot0\cdot0)-(1\cdot4\cdot3)=0+0+16-(-15)-0-12=19$
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