Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 3 - Determinants - 3.1 Exercises - Page 170: 17

Answer

$-10$

Work Step by Step

$\det A=(2\cdot2\cdot(-1))+((-3)\cdot2\cdot1)+(3\cdot3\cdot3)-(1\cdot2\cdot3)-(3\cdot2\cdot2)-((-1)\cdot3\cdot(-3))=(-4)+(-6)+27-6-12-9=-10$
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