Answer
$24$
Work Step by Step
$\det A=(1\cdot3\cdot(-2))+(0\cdot2\cdot0)+(4\cdot2\cdot5)-(0\cdot3\cdot4)-(5\cdot2\cdot1)-((-2)\cdot2\cdot0)=-6+0+40-0-10-0=24$
Linear Algebra and Its Applications (5th Edition)
by Lay, David C.; Lay, Steven R.; McDonald, Judi J.
Published by
Pearson
ISBN 10:
032198238X
ISBN 13:
978-0-32198-238-4
Chapter 3 - Determinants - 3.1 Exercises - Page 170: 15
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