Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 8

Answer

$11y(y+5)$

Work Step by Step

Step 1. Factor both denominators. $\left\{\begin{array}{ll} 11(y+5) & \\ y & \end{array}\right.\qquad $(already factored) Step 2. List the factors of the first denominator. $ List=11,(y+5)...\qquad$ (list in progress) Step 3. Add to the list in step 2 any factors of the second denominator that are not yet listed. $y$ is not in the list, we add it to the list $List=11,(y+5),y$ Step 4. LCD is the product of the listed factors. $LCD=11y(y+5)$
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