Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 18

Answer

$\displaystyle \frac{4x+8}{x^{2}}$

Work Step by Step

Step 1: Find the LCD. List of factors of the first denominator: $\qquad x.$ List of factors of the second denominator: $\qquad x,x$ Build the LCD: - write all factors of the 1st denominator:$\qquad $List$=x...\quad$ (for now) - add to the list factors of the second denominator that are not already on the list (one x is already in, we add the second x) List = $x,x$ $LCD=x^{2}$ Step 2. Rewrite each expression with the LCD: $\displaystyle \frac{4}{x}\cdot\frac{x}{x}+\frac{8}{x^{2}}=\frac{4x}{x^{2}}+\frac{8}{x^{2}}=...$ Step 3. Combine numerators over the LCD $=\displaystyle \frac{4x+8}{x^{2}}$ Step 4. Simplify, if possible. $=\displaystyle \frac{4(x+2)}{x^{2}} \qquad$... nothing to simplify.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.