Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 28

Answer

$\displaystyle \frac{3x+11}{4}$

Work Step by Step

Step 1: Find the LCD. List of factors of the first denominator: $\qquad 2$ List of factors of the second denominator: $\qquad 2,2$ Build the LCD: - write all factors of the 1st denominator:$\qquad $ List$=2,...\quad$ (for now) - add to the list factors of the second denominator that are not already on the list (a 2 is added to the list) List = $2,2, $ $LCD=4$ Step 2. Rewrite each expression with the LCD: $=\displaystyle \frac{x+3}{2}\cdot\frac{2}{2}+\frac{x+5}{4}= \displaystyle \frac{2(x+3)}{4}+\frac{x+5}{4}=...$ Step 3. Combine numerators over the LCD $= \displaystyle \frac{2(x+3)+x+5}{4} $ Step 4. Simplify, if possible. $= \displaystyle \frac{2x+6+x+5}{4} $ = $\displaystyle \frac{3x+11}{4}$
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