Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 35

Answer

$ -\displaystyle \frac{7}{x+7}$

Work Step by Step

$\displaystyle \frac{x}{x+7}-1=\frac{x}{x+7}-\frac{1}{1}$ Step 1: Find the LCD. List of factors of the first denominator: $\qquad (x+7)$ List of factors of the second denominator: $\qquad 1$ Build the LCD: - write all factors of the 1st denominator:$\qquad $ List$= (x+7),...\quad$ (for now) - add to the list factors of the second denominator that are not already on the list ($1$ is added to the list) List = $(x+7),1$ $LCD=(x+7)$ Step 2. Rewrite each expression with the LCD: $=\displaystyle \frac{x}{x+7}-\frac{1}{1}\cdot\frac{(x+7)}{(x+7)}= \frac{x}{x+7} -\frac{x+7}{x+7}=...$ Step 3. Combine numerators over the LCD $=$ $ \displaystyle \frac{x-(x+7)}{x+7} $ Step 4. Simplify, if possible. $= \displaystyle \frac{x-x-7}{x+7}$ = $ -\displaystyle \frac{7}{x+7}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.