Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 22

Answer

$ \displaystyle \frac{50x+3}{5x^{2}} $

Work Step by Step

Step 1: Find the LCD. List of factors of the first denominator: $\qquad x.$ List of factors of the second denominator: $\qquad 5,x,x$ Build the LCD: - write all factors of the 1st denominator:$\qquad $List$=x...\quad$ (for now) - add to the list factors of the second denominator that are not already on the list (one $x$ is already in, we add the other $x$ and the $5$ to the list) List = $x,x,5,$ $LCD=5x^{2}$ Step 2. Rewrite each expression with the LCD: $\displaystyle \frac{10}{x}\cdot\frac{5x}{5x}+\frac{3}{5x^{2}}=\frac{50x}{5x^{2}}+\frac{3}{5x^{2}}=...$ Step 3. Combine numerators over the LCD $= \displaystyle \frac{50x+3}{5x^{2}} $ Step 4. Simplify, if possible. ... nothing to simplify =$ \displaystyle \frac{50x+3}{5x^{2}} $
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