Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 12

Answer

$y(y+7)(y-7)$

Work Step by Step

Step 1. Factor both denominators. The first one is a difference of squares, the second is already factored. $\left\{\begin{array}{lll} y^{2}-49 & =y^{2}-7^{2} & =(y+7)(y-7)\\ y(y-7) & & \end{array}\right.$ Step 2. List the factors of the first denominator. $ List=(y+7),(y-7),...\qquad$ (list in progress) Step 3. Add to the list in step 2 any factors of the second denominator that are not yet listed. $y$ is not in the list, we add it to the list $List=(y+7),(y-7),y,...$ $(y-7)$ is already in the list, do not add it. Step 4. LCD is the product of the listed factors. $LCD=y(y+7)(y-7)$
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