Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 25

Answer

$ \displaystyle \frac{2+9x}{x} $

Work Step by Step

$\displaystyle \frac{2}{x}+9=\frac{2}{x}+\frac{9}{1}$ Step 1: Find the LCD. List of factors of the first denominator: $\qquad x.$ List of factors of the second denominator: $\qquad 1$ Build the LCD: - write all factors of the 1st denominator:$\qquad $List$=x,...\quad$ (for now) - add to the list factors of the second denominator that are not already on the list List = $x,1, $ $LCD=x$ Step 2. Rewrite each expression with the LCD: $\displaystyle \frac{2}{x}+\frac{9}{1}\cdot\frac{x}{x}=\frac{2}{x}+\frac{9x}{x}=...$ Step 3. Combine numerators over the LCD $= \displaystyle \frac{2+9x}{x} $ Step 4. Simplify, if possible. ... nothing to simplify =$ \displaystyle \frac{2+9x}{x} $
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