Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Exercise Set - Page 517: 10

Answer

$(x-6)(x+6)$

Work Step by Step

Step 1. Factor both denominators. The first one is already factored, the second is a difference of squares. $\left\{\begin{array}{lll} (x-6) & & \\ x^{2}-36 & =x^{2}-6^{2} & =(x-6)(x+6) \end{array}\right.$ Step 2. List the factors of the first denominator. $ List=(x-6),...\qquad$ (list in progress) Step 3. Add to the list in step 2 any factors of the second denominator that are not yet listed. $(x-6)$ is already in the list, do not add it. $(x+6)$ is not in the list, we add it to the list $List=(x-6),(x+6)$ Step 4. LCD is the product of the listed factors. $LCD=(x-6)(x+6)$
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