Answer
$5$
Work Step by Step
RECALL:
$\log_b{a}-\log_b{c} = \log_b{(\frac{a}{c})}$
Use the rule above to obtain:
$=\log_2{(\frac{96}{3})}
\\=\log_2{32}$
Write $32$ as $2^5$ to obtain:
$=\log_2{2^5}$
Use the rule $\log_b{b^x} = x$ to obtain:
$=5$