Answer
$\log_8{(13 \cdot 7)} = \log_8{13} + \log_8{7}$
Work Step by Step
RECALL:
The product rule for logarithms:
$\log_a{bc} = \log_a{b} + \log_a{c}$
Use the product rule to obtain:
$\log_8{(13 \cdot 7)} = \log_8{13} + \log_8{7}$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set - Page 712: 2
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