Answer
$\log_5{(7 \cdot 3)} = \log_5{7} + \log_5{3}$
Work Step by Step
RECALL:
The product rule for logarithms:
$\log_a{bc} = \log_a{b} + \log_a{c}$
Use the product rule to obtain:
$\log_5{(7 \cdot 3)} = \log_5{7} + \log_5{3}$
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