Answer
$1+\log_7{x}$
Work Step by Step
RECALL:
The product rule for logarithms:
$\log_a{bc} = \log_a{b} + \log_a{c}$
Use the product rule to obtain:
$\log_7{(7x)}
\\= \log_7{(7 \cdot x)}
\\= \log_7{7} + \log_7{x}$
Note that for all real numbers within its domain, $\log_a{a}=1$.
This means that $\log_7{7} = 1$.
Thus,
$\log_7{7} + \log_7{x}= 1 + \log_7{x}$
