Answer
$\ln{(x^{\frac{1}{2}}y)}$
Work Step by Step
RECALL:
(1) $\ln{a}-\ln{c} = \ln{(\frac{a}{c})}$
(2) $\ln{a} + \ln{c} = \ln{ac}$
(3) $a \cdot \ln{x} = \ln{x^{a}}$
Use rule (3) above to obtain:
$=\ln{(x^{\frac{1}{2}})}+\ln{(y)}$
Use rule (2) above to obtain:
$=\ln{(x^{\frac{1}{2}}y)}$
