Answer
$3$
Work Step by Step
RECALL:
$\log{a}+\log{b} = \log{ab}$
Use the rule above to obtain:
$=\log{(250\cdot 4)}
\\=\log{1000}$
Write $1000$ as $10^3$ to obtain:
$=\log{10^3}$
Use the rule $\log{10^x} = x$ to obtain:
$=3$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set - Page 712: 38
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