Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set: 38

Answer

$3$

Work Step by Step

RECALL: $\log{a}+\log{b} = \log{ab}$ Use the rule above to obtain: $=\log{(250\cdot 4)} \\=\log{1000}$ Write $1000$ as $10^3$ to obtain: $=\log{10^3}$ Use the rule $\log{10^x} = x$ to obtain: $=3$
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