Answer
$2-\ln{5}$
Work Step by Step
RECALL:
The quotient rule for logarithms states:
$\ln(\frac{b}{c})=\ln{b}−\ln{c}$
Use the quotient rule to obtain:
$=\ln(e^2))-\ln{5}$
Note that for all real numbers within its domain, $\ln{(e^n)}=n$.
This means that $\ln{(e^2)}=2$.
Thus,
$\ln{(e^2)}-\ln{5}=2-\ln{5}$
