Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 9 - Section 9.4 - Properties of Logarithms - Exercise Set - Page 712: 35

Answer

$\frac{2}{3}\log_5 {x}+\frac{1}{3}\log_5 {y}- \frac{2}{3} $.

Work Step by Step

The given expression is $=\log_5{\sqrt[3] { \frac{x^2 y}{25} }}$ $=\log_5{\left( \frac{x^2 y}{25} \right )^{\frac{1}{3}} }$ Use power rule. $=\frac{1}{3} \log_5{\left( \frac{x^2 y}{25} \right ) }$ Use the quotient rule. $\frac{1}{3} ( \log_5 {x^2y}- \log_5{25} )$ Use the product rule. $\frac{1}{3} ( \log_5 {x^2}+\log_5 {y}- \log_5{25} )$ $\frac{1}{3} ( \log_5 {x^2}+\log_5 {y}- \log_5{5^2} )$ Use the power rule. $\frac{1}{3} ( 2\log_5 {x}+\log_5 {y}- 2\log_5{5} )$ Use $\log _aa = 1$. $\frac{1}{3} ( 2\log_5 {x}+\log_5 {y}- 2 )$ Clear the parentheses. $\frac{2}{3}\log_5 {x}+\frac{1}{3}\log_5 {y}- \frac{2}{3} $.
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