Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set: 8

Answer

$\frac{107}{105}$

Work Step by Step

We sum from i = low bound to i = high bound. $\frac{2}{2+3} + \frac{2}{3+3} + \frac{2}{4+3} = \frac{2}{5} + \frac{2}{6} + \frac{2}{7} = \frac{84}{210} + \frac{70}{210} + \frac{60}{210} = \frac{214}{210} = \frac{107}{105}$
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