Answer
$-24$
Work Step by Step
The first two terms of $
a_n=(n+2)(n-5)
$ are
\begin{array}{l}
a_1=(1+2)(1-5)\\
a_1=(3)(-4)\\
a_1=-12
,\\\\
a_2=(2+2)(2-5)\\
a_2=(4)(-3)\\
a_2=-12
.\end{array}
Hence, the partial sum is $
-12+(-12)=
-24
$.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 11 - Section 11.3 - Series - Exercise Set - Page 651: 29
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