Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set - Page 651: 23

Answer

$\displaystyle\sum_{i=1}^{6}(15-3i)$

Work Step by Step

Using the summation notation, the series $ 12+9+6+3+0+(-3) $ is equivalent to \begin{array}{l} \displaystyle\sum_{i=1}^{6}(15-3i) .\end{array}
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