Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set: 13

Answer

$74$

Work Step by Step

We sum from i = low bound to i = high bound. $3(3+2) + 4(4+2) + 5(5+2) = 3(5) + 4(6) +5(7) = 15 + 24 + 35 = 74$
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