Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set - Page 651: 9

Answer

$\frac{11}{36}$

Work Step by Step

We sum from i = low bound to i = high bound. $\frac{1}{6} + \frac{1}{12} + \frac{1}{18} = \frac{6}{36} + \frac{3}{36} + \frac{2}{36} = \frac{11}{36}$
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