Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set: 5

Answer

$20$

Work Step by Step

We sum from i = low bound to i = high bound. $(2^2-3) + (3^2-3) + (4^2-3) = (4-3) + (9-3) + (16-3) = 1 + 6 + 13 = 20$
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