Work Step by Step
We sum from i = low bound to i = high bound. $(2^2-3) + (3^2-3) + (4^2-3) = (4-3) + (9-3) + (16-3) = 1 + 6 + 13 = 20$
You can help us out by revising, improving and updating this answer.Update this answer
After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.