Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Section 11.3 - Series - Exercise Set: 7

Answer

$\frac{73}{168}$

Work Step by Step

We sum from i = low bound to i = high bound. $\frac{1}{1+5} + \frac{1}{2+5} + \frac{1}{3+5} = \frac{1}{6} + \frac{1}{7} + \frac{1}{8} = \frac{28}{168} + \frac{24}{168} + \frac{21}{168} = \frac{73}{168}$
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