Answer
$
1
$
Work Step by Step
The first 7 terms of $
a_n=(-1)^{n-1}
$ are
\begin{array}{l}
a_1=(-1)^{1-1}\\
a_1=(-1)^{0}\\
a_1=1
,\\\\
a_2=(-1)^{2-1}\\
a_2=(-1)^{1}\\
a_2=-1
,\\\\
a_3=(-1)^{3-1}\\
a_3=(-1)^{2}\\
a_3=1
,\\\\
a_4=(-1)^{4-1}\\
a_4=(-1)^{3}\\
a_4=-1
,\\\\
a_5=(-1)^{5-1}\\
a_5=(-1)^{4}\\
a_5=1
,\\\\
a_6=(-1)^{6-1}\\
a_6=(-1)^{5}\\
a_6=-1
,\\\\
a_7=(-1)^{7-1}\\
a_7=(-1)^{6}\\
a_7=1
.\end{array}
Hence, the partial sum is $
1-1+1-1+1-1+1=
1
$.