Answer
$1+\frac{41}{330} = \frac{371}{330}$
Work Step by Step
We sum from i = low bound to i = high bound.
$\frac{6-2}{6+2} + \frac{6-3}{6+3} + \frac{6-4}{6+4} + \frac{6-5}{6+5} = \frac{4}{8} + \frac{3}{9} + \frac{2}{10} + \frac{1}{11}$
$=\frac{1}{2} + \frac{1}{3} + \frac{1}{5} + \frac{1}{11} = \frac{341}{330} + \frac{30}{330} = \frac{371}{330} = 1+\frac{41}{330}$
