Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review: 32c

Answer

$\log_{2} \frac{x^{5}}{(x-1)^{2}}$

Work Step by Step

$2\log_{2} x+3\log_{2} x-2\log_{2} (x-1)$ =$\log_{2} x^{2}+\log_{2} x^{3}-\log_{2} (x-1)^{2}$ =$(\log_{2} x^{2}+\log_{2} x^{3})-\log_{2} (x-1)^{2}$ =$\log_{2} (x^{2} \times x^{3})-\log_{2} (x-1)^{2}$ =$\log_{2} (x^{5})-\log_{2} (x-1)^{2}$ =$\log_{2} \frac{x^{5}}{(x-1)^{2}}$
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