Answer
$y=\{-5,-1,1\}$
Work Step by Step
Expressing the equation $
y^3+5y^2-y=5
$ in factored form results to
\begin{array}{l}\require{cancel}
y^3+5y^2-y-5=0\\
y^2(y+5)-(y+5)=0\\
(y+5)(y^2-1)=0\\
(y+5)(y+1)(y-1)=0
.\end{array}
Equating each factor to zero, then the solution set is $
y=\{-5,-1,1\}
.$
