Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 11d

Answer

$2\sqrt[4]{2}$

Work Step by Step

Using properties of radicals, the expression $ \sqrt[4]{32} $ simplifies to \begin{array}{l}\require{cancel} \sqrt[4]{16\cdot2} \\= 2\sqrt[4]{2} .\end{array}
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