Answer
$\log_{3} 6$
Work Step by Step
Using properties of logarithms, the expression $
\log_{3} \dfrac{1}{2}+\log_{3} 12
$ is equivalent to
\begin{array}{l}
\log_{3} \left( \dfrac{1}{2}\cdot12 \right)
\\=
\log_{3} 6
.\end{array}
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