Answer
$(f \circ g)(2) = 25$
$(g \circ f)(2) = 7$
Work Step by Step
RECALL:
(1) $(f \circ g)(x) = f[g(x)]$
(2) $(g \circ f)(x) = g[f(x)]$
Thus,
$(f\circ g)(x)= f[(g(x)]
\\(f\circ g)(x)=(x+3)^2$
and
$(g \circ f)(x) = g[f(x)]$
$(g \circ f)(x) = x^2+3$
Substitute $2$ into $x$ to obtain:
$(f\circ g)(x)=(x+3)^2
\\(f\circ g)(2)=(2+3)^2 = 5^2 = 25$
and
$(g \circ f)(x) = x^2+3
\\$(g \circ f)(x) = 2^2+3=4+3=7$
