Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 48a

Answer

$40$

Work Step by Step

Using the definition of the summation symbol, $\displaystyle\sum_{i=0}^4 i(i+1) $ evaluates to \begin{array}{l} 0(0+1)+1(1+1)+2(2+1)+3(3+1)+4(4+1) \\= 0+2+6+12+20 \\= 40 .\end{array}
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