Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 33

Answer

$x=\dfrac{\log7}{\log3}$

Work Step by Step

Taking the logarithm of both sides, then the values of $x$ in the equation $ 3^x=7 $ is \begin{array}{l} \log3^x=\log7 \\ x(\log3)=\log7 \\ x=\dfrac{\log7}{\log3} .\end{array}
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