Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 49

Answer

$S_{30}=465$

Work Step by Step

The first 30 positive integers is an arithmetic sequence with $a_1=1$ and $a_n=30$. Using $S_n=\dfrac{n}{2}(a_1+a_n)$, then, \begin{array}{l} S_{30}=\dfrac{30}{2}(1+30) \\ S_{30}=15(31) \\ S_{30}=465 .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.