Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 30b

Answer

$-3$

Work Step by Step

Using the property $\log_b b^x=x$ then the expression $ \log 10^{-3} $ is equal to \begin{array}{l} \log_{10} 10^{-3} \\= -3(\log_{10} 10) \\= -3(1) \\= -3 .\end{array}
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