College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 41

Answer

$\frac{3x+7}{(x+5)(x-3)}$

Work Step by Step

We form a common denominator: $\displaystyle \frac{1}{x+5}+\frac{2}{x-3}=\frac{x-3}{(x+5)(x-3)}+\frac{2(x+5)}{(x+5)(x-3)}=\frac{x-3+2x+10}{(x+5)(x-3)}=\frac{3x+7}{(x+5)(x-3)}$
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