College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises - Page 51: 23

Answer

$\frac{x(2x+3)}{2x-3}$

Work Step by Step

We simplify: $\displaystyle \frac{2x^{3}-x^{2}-6x}{2x^{2}-7x+6}=\frac{x(2x^{2}-x-6)}{(2x-3)(x-2)}=\frac{x(2x+3)(x-2)}{(2x-3)(x-2)}=\frac{x(2x+3)}{2x-3}$
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