## College Algebra 7th Edition

$\frac{x-5}{x-4}$
We simplify by factoring the left side and reducing with $x+4$ and $x+5$: $\displaystyle \frac{x^{2}-25}{x^{2}-16}*\frac{x+4}{x+5}=\frac{(x-5)(x+5)}{(x-4)(x+4)}*\frac{x+4}{x+5}=\frac{x-5}{x-4}$