College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 34

Answer

$\frac{1}{(2x-5)(3x-2)}$

Work Step by Step

We switch from division to multiplication by taking the reciprocal of the right fraction. Then we factor and simplify: $\displaystyle \frac{2x+1}{2x^{2}+x-15}\div\frac{6x^{2}-x-2}{x+3}=\frac{2x+1}{(x+3)(2x-5)}*\frac{x+3}{(2x+1)(3x-2)}=\frac{1}{(2x-5)(3x-2)}$
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