College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 45

Answer

$\frac{2(5x-9)}{(2x-3)^{2}}$

Work Step by Step

We form a common denominator: $\displaystyle \frac{5}{2x-3}-\frac{3}{(2x-3)^{2}}=\frac{5(2x-3)}{(2x-3)^{2}}-\frac{3}{(2x-3)^{2}}=\frac{10x-15-3}{(2x-3)^{2}}=\frac{10x-18}{(2x-3)^{2}}=\frac{2(5x-9)}{(2x-3)^{2}}$
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