Answer
$\frac{-2x-1}{(x-3)(x+2)}$
Work Step by Step
We form a common denominator, then add, factor, and simplify:
$\displaystyle \frac{x}{x^{2}-x-6}-\frac{1}{x+2}-\frac{2}{x-3}=\frac{x}{(x-3)(x+2)}+\frac{-1}{x+2}+\frac{-2}{x-3}
=\frac{x}{(x-3)(x+2)}+\frac{-1(x-3)}{(x-3)(x+2)}+\frac{-2(x+2)}{(x-3)(x+2)}=\frac{x-x+3-2x-4}{(x-3)(x+2)}=\frac{-2x-1}{(x-3)(x+2)}$
