## College Algebra 7th Edition

$\dfrac{1}{x+2}$
Factor the denominator to obtain: $=\dfrac{x-2}{(x-2)(x+2)}$ Cancel the common factor to obtain: $\require{cancel} =\dfrac{\cancel{x-2}}{\cancel{(x-2)}(x+2)} \\=\dfrac{1}{x+2}$