College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises - Page 51: 17

Answer

$\dfrac{1}{x+2}$

Work Step by Step

Factor the denominator to obtain: $=\dfrac{x-2}{(x-2)(x+2)}$ Cancel the common factor to obtain: $\require{cancel} =\dfrac{\cancel{x-2}}{\cancel{(x-2)}(x+2)} \\=\dfrac{1}{x+2}$
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