College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.7 - Rational Expressions - P.7 Exercises: 29

Answer

$\frac{1}{t^{2}+9}$

Work Step by Step

We factor the denominators and reduce: $\displaystyle \frac{t-3}{t^{2}+9}*\displaystyle \frac{t+3}{t^{2}-9}=\frac{(t-3)(t+3)}{(t^{2}+9)(t-3)(t+3)}=\frac{1}{t^{2}+9}$
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