Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter 7 - Section 7.1 - Simplifying Rational Expressions - Exercise Set: 53

Answer

$\dfrac{x^{2}-1}{x^{2}-2x+1}=\dfrac{x+1}{x-1}$

Work Step by Step

$\dfrac{x^{2}-1}{x^{2}-2x+1}$ Factor the numerator: $\dfrac{x^{2}-1}{x^{2}-2x+1}=\dfrac{(x-1)(x+1)}{x^{2}-2x+1}=...$ Factor the perfect square trinomial in the denominator. Then, simplify: $...=\dfrac{(x-1)(x+1)}{(x-1)^{2}}=\dfrac{x+1}{x-1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.