Answer
$\dfrac{2x^{2}+7x-4}{x^2+3x-4}=\dfrac{2x-1}{x-1}$
Work Step by Step
$\dfrac{2x^{2}+7x-4}{x^2+3x-4}$
Factor the numerator:
$\dfrac{2x^{2}+7x-4}{x^2+3x-4}=\dfrac{(x+4)(2x-1)}{x^{2}+3x-4}=...$
Factor the denominator and then, simplify:
$...=\dfrac{(x+4)(2x-1)}{(x+4)(x-1)}=\dfrac{2x-1}{x-1}$
