Answer
$\dfrac{x^{3}+7x^{2}}{x^{2}+5x-14}=\dfrac{x^{2}}{x-2}$
Work Step by Step
$\dfrac{x^{3}+7x^{2}}{x^{2}+5x-14}$
Take out common factor $x^{2}$ in the numerator:
$\dfrac{x^{3}+7x^{2}}{x^{2}+5x-14}=\dfrac{x^{2}(x+7)}{x^{2}+5x-14}=...$
Factor the denominator and simplify:
$...=\dfrac{x^{2}(x+7)}{(x+7)(x-2)}=\dfrac{x^{2}}{x-2}$
